(x^3-2)-[2x^3-(3x+4)]=0

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Solution for (x^3-2)-[2x^3-(3x+4)]=0 equation:


Simplifying
(x3 + -2) + -1[2x3 + -1(3x + 4)] = 0

Reorder the terms:
(-2 + x3) + -1[2x3 + -1(3x + 4)] = 0

Remove parenthesis around (-2 + x3)
-2 + x3 + -1[2x3 + -1(3x + 4)] = 0

Reorder the terms:
-2 + x3 + -1[2x3 + -1(4 + 3x)] = 0
-2 + x3 + -1[2x3 + (4 * -1 + 3x * -1)] = 0
-2 + x3 + -1[2x3 + (-4 + -3x)] = 0

Reorder the terms:
-2 + x3 + -1[-4 + -3x + 2x3] = 0
-2 + x3 + [-4 * -1 + -3x * -1 + 2x3 * -1] = 0
-2 + x3 + [4 + 3x + -2x3] = 0

Reorder the terms:
-2 + 4 + 3x + x3 + -2x3 = 0

Combine like terms: -2 + 4 = 2
2 + 3x + x3 + -2x3 = 0

Combine like terms: x3 + -2x3 = -1x3
2 + 3x + -1x3 = 0

Solving
2 + 3x + -1x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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